What is the derivative of y=e^{-4x} ?

The derivative of y=e^{-4x} is -4e^{-4x}

What is the first derivative of y=e^{-4x} ?

The first derivative of y=e^{-4x} is -4e^{-4x}

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derivative of

y = e^{- 4 x}

- 4 e^{- 4 x}

Solution steps

\frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= e^{- 4 x} (- 4)

Simplify

= - 4 e^{- 4 x}

x^{3} + 8, x + 8

\frac{6 x}{( x ^{2} + 1 )}

\frac{\partial}{\partial y} (\frac{e ^{x y}}{x + y})

\int \frac{1}{y ^{2} + y + 1} d y

\frac{d}{d x} (e^{l n (c o s (x^{2}))} 2 x + 1)

What is the derivative of y=e^{-4x} ?
The derivative of y=e^{-4x} is -4e^{-4x}
What is the first derivative of y=e^{-4x} ?
The first derivative of y=e^{-4x} is -4e^{-4x}