What is the tangent of f(x)= 5/(x-4),\at x=3 ?

The tangent of f(x)= 5/(x-4),\at x=3 is y=-5x+10

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tangent of f(x)= 5/(x-4),\at x=3

tangent of

f (x) = \frac{5}{x - 4}, at x = 3

y = - 5 x + 10

Solution steps

Find the tangent point:

(3, - 5)

Find the slope of

f (x) = \frac{5}{x - 4} : \frac{df ( x )}{d x} = - \frac{5}{( x - 4 ) ^{2}}

Compute the slope of

f (x) = \frac{5}{x - 4}

x = 3 : m = - 5

Find the line with slope m=

- 5

and passing through

(3, - 5) : y = - 5 x + 10

y = - 5 x + 10

\int t^{2} - 5 t + 4 d t

\int \frac{x ^{2}}{x} d x

f (x) = - 5 x^{2} - 3 x, at x = - 3

\frac{d}{d x} (\frac{3 x + 1}{x ^{\frac{2}{3}}})

\int e^{\frac{- 1}{x}} d x

What is the tangent of f(x)= 5/(x-4),\at x=3 ?
The tangent of f(x)= 5/(x-4),\at x=3 is y=-5x+10