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Popular >

integral from 0 to 2 of (2x-1)

Solution

\int_{0}^{2} (2 x - 1) d x

Solution

2

Solution steps

\int_{0}^{2} 2 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x d x - \int_{0}^{2} 1 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= 4 - 2

Simplify

= 2

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (2x-1) ?
The integral from 0 to 2 of (2x-1) is 2