What is the integral of (x^2)/(5-x^3) ?

The integral of (x^2)/(5-x^3) is -1/3 ln|5-x^3|+C

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integral of (x^2)/(5-x^3)

\int \frac{x ^{2}}{5 - x ^{3}} d x

- \frac{1}{3} ln 5 - x^{3} + C

Solution steps

\int \frac{x ^{2}}{5 - x ^{3}} d x

Apply u-substitution

: \int - \frac{1}{3 u} d u

= \int - \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{3} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{3} ln ∣ u ∣

Substitute back

u = 5 - x^{3}

= - \frac{1}{3} ln 5 - x^{3}

Add a constant to the solution

= - \frac{1}{3} ln 5 - x^{3} + C

\frac{d}{d x} (\frac{( x ^{2} + x ) ( 2 x + 1 )}{4 x})

\int 4 x - x e^{x} + e d x

\frac{\partial}{\partial y} (2 x y e^{x^{2}})

\frac{d}{d x} (- x^{4} cos (x))

n = 1 \sum \infty n^{n}

What is the integral of (x^2)/(5-x^3) ?
The integral of (x^2)/(5-x^3) is -1/3 ln|5-x^3|+C