What is (\partial)/(\partial x)(cos(6y-x)) ?

The answer to (\partial)/(\partial x)(cos(6y-x)) is sin(6y-x)

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(\partial)/(\partial x)(cos(6y-x))

\frac{\partial}{\partial x} (cos (6 y - x))

sin (6 y - x)

Solution steps

\frac{\partial}{\partial x} (cos (6 y - x))

Treat

y

as a constant

Apply the chain rule:

- sin (6 y - x) \frac{\partial}{\partial x} (6 y - x)

= - sin (6 y - x) \frac{\partial}{\partial x} (6 y - x)

\frac{\partial}{\partial x} (6 y - x) = - 1

= - sin (6 y - x) (- 1)

Simplify

= sin (6 y - x)

20 + x - x^{2}, x^{2} - 5 x

7^{x}

\frac{d}{d x} (arccsc (2 x^{2} + 1))

\int \frac{1}{( x \cdot ( x ^{2} ) + 4 )} d x

(x + 8 y) y^{^{'}} = 2 x - y

What is (\partial)/(\partial x)(cos(6y-x)) ?
The answer to (\partial)/(\partial x)(cos(6y-x)) is sin(6y-x)