What is the derivative of f(x)=x^4-x^2 ?

The derivative of f(x)=x^4-x^2 is 4x^3-2x

What is the first derivative of f(x)=x^4-x^2 ?

The first derivative of f(x)=x^4-x^2 is 4x^3-2x

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derivative of

f (x) = x^{4} - x^{2}

4 x^{3} - 2 x

Solution steps

\frac{d}{d x} (x^{4} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (x^{2}) = 2 x

= 4 x^{3} - 2 x

t (\frac{d x}{d t}) + 3 x = 5 t^{2}

\int \frac{( x + 1 ) ^{2}}{x ^{2} - 1} d x

\frac{d}{d x} (12 x^{3} + 12 x^{2})

\int \frac{x - x ^{3} e ^{x} + x ^{2}}{x ^{3}} d x

x \to 0 lim (x cos (\frac{11}{2} x))

What is the derivative of f(x)=x^4-x^2 ?
The derivative of f(x)=x^4-x^2 is 4x^3-2x
What is the first derivative of f(x)=x^4-x^2 ?
The first derivative of f(x)=x^4-x^2 is 4x^3-2x