What is the integral from 0 to infinity of 7e^{-x} ?

The integral from 0 to infinity of 7e^{-x} is 7

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integral from 0 to infinity of 7e^{-x}

\int_{0}^{\infty} 7 e^{- x} d x

7

Solution steps

\int_{0}^{\infty} 7 e^{- x} d x

Compute the indefinite integral:

\int 7 e^{- x} d x = - 7 e^{- x} + C

Compute the boundaries:

\int_{0}^{\infty} 7 e^{- x} d x = 0 - (- 7)

= 0 - (- 7)

Simplify

= 7

x \to 0 lim (2 x + 1)

\frac{d}{d x} (\frac{1}{2 x + 12})

\frac{\partial}{\partial x} (\frac{x \cdot d}{n \cdot L ( x , d )})

\frac{\partial}{\partial x} (x y + z)

\frac{d}{d t} ((t (y^{2} + y))^{- 1})

What is the integral from 0 to infinity of 7e^{-x} ?
The integral from 0 to infinity of 7e^{-x} is 7