What is the tangent of x^2-2,\at x=3 ?

The tangent of x^2-2,\at x=3 is y=6x-11

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tangent of x^2-2,\at x=3

tangent of

x^{2} - 2, at x = 3

y = 6 x - 11

Solution steps

Find the tangent point:

(3, 7)

Find the slope of

y = x^{2} - 2 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 2

x = 3 : m = 6

Find the line with slope m=

6

and passing through

(3, 7) : y = 6 x - 11

y = 6 x - 11

\int \frac{2 cos ( x )}{3 sin ^{2} ( x )} d x

\int 3 sin (\frac{x}{2}) d x

\int_{1}^{2} (4 x^{3} - 3 x^{2} + 2 x) d x

\int cos (3 x - 1) d x

\int (3 t e^{t}, ln (t)) d t