What is area y=x^2,y=sqrt(8+x) ?

The answer to area y=x^2,y=sqrt(8+x) is 6.35121…

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area y=x^2,y=sqrt(8+x)

area

y = x^{2}, y = 8 + x

6.35121 \dots

Solution steps

Apply the area formula:

\int_{- 1.59109 \dots}^{1.76786 \dots} x^{2} - 8 + x d x

Solve

\int_{- 1.59109 \dots}^{1.76786 \dots} x^{2} - 8 + x d x : 6.35121 \dots

The area is:

= 6.35121 \dots

\int 100 t^{2} + 36 t^{4} d t

9 \frac{d}{d x} (\frac{d y}{d x}) + 10 y = 0

x \to - 3 - lim (\frac{x}{x + 3})

x \to 0 lim ((x) (ln (x))^{2})

\frac{d}{d x} (sin (x) x)

What is area y=x^2,y=sqrt(8+x) ?
The answer to area y=x^2,y=sqrt(8+x) is 6.35121…