What is the integral of (e^x)/((e^x+1)) ?

The integral of (e^x)/((e^x+1)) is ln|e^x+1|+C

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integral of (e^x)/((e^x+1))

\int \frac{e ^{x}}{( e ^{x} + 1 )} d x

ln ∣ e^{x} + 1 ∣ + C

Solution steps

\int \frac{e ^{x}}{e ^{x} + 1} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = e^{x} + 1

= ln ∣ e^{x} + 1 ∣

Add a constant to the solution

= ln ∣ e^{x} + 1 ∣ + C

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What is the integral of (e^x)/((e^x+1)) ?
The integral of (e^x)/((e^x+1)) is ln|e^x+1|+C