What is the tangent of-4x^2+7x ?

The tangent of-4x^2+7x is y=(-8a_{0}+7)x+4a_{0}^2

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tangent of-4x^2+7x

tangent of

- 4 x^{2} + 7 x

y = (- 8 a_{0} + 7) x + 4 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 4 a_{0}^{2} + 7 a_{0})

Find the slope of

y = - 4 x^{2} + 7 x : \frac{d y}{d x} = - 8 x + 7

Compute the slope of

y = - 4 x^{2} + 7 x

x = a_{0} : m = - 8 a_{0} + 7

Find the line with slope m=

- 8 a_{0} + 7

and passing through

(a_{0}, - 4 a_{0}^{2} + 7 a_{0}) : y = (- 8 a_{0} + 7) x + 4 a_{0}^{2}

y = (- 8 a_{0} + 7) x + 4 a_{0}^{2}

n = 3 \sum \infty e^{5 - 4 n}

\int \frac{- x}{( x ^{2} + 1 ) ^{2}} d x

x \to - 3 lim (\frac{3 - ∣ x ∣}{x + 3})

y^{^{''}} + 17 y^{^{'}} + 70 y = 0

(- 5, - 2), (3, - 9)

What is the tangent of-4x^2+7x ?
The tangent of-4x^2+7x is y=(-8a_{0}+7)x+4a_{0}^2