What is the d/(dz)((z^2)/2-(z^7)/7) ?

The d/(dz)((z^2)/2-(z^7)/7) is z-z^6

What is the first d/(dz)((z^2)/2-(z^7)/7) ?

The first d/(dz)((z^2)/2-(z^7)/7) is z-z^6

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\frac{d}{d z} (\frac{z ^{2}}{2} - \frac{z ^{7}}{7})

z - z^{6}

Solution steps

\frac{d}{d z} (\frac{z ^{2}}{2} - \frac{z ^{7}}{7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d z} (\frac{z ^{2}}{2}) - \frac{d}{d z} (\frac{z ^{7}}{7})

\frac{d}{d z} (\frac{z ^{2}}{2}) = z

\frac{d}{d z} (\frac{z ^{7}}{7}) = z^{6}

= z - z^{6}

\frac{d}{d x} (x cos (x))

\int cos^{7} (x) tan^{3} (x) d x

\frac{d}{d x} (x^{5})

\int \frac{8 x}{1 - x ^{4}} d x

\int (cos^{7} (x)) sin (x) d x

What is the d/(dz)((z^2)/2-(z^7)/7) ?
The d/(dz)((z^2)/2-(z^7)/7) is z-z^6
What is the first d/(dz)((z^2)/2-(z^7)/7) ?
The first d/(dz)((z^2)/2-(z^7)/7) is z-z^6