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Popular >

y^'+y/x =2x^4y^2

Solution

y^{^{'}} + \frac{y}{x} = 2 x^{4} y^{2}

Solution

y = \frac{2}{x ( - x ^{4} + c _{1} )}

Solution steps

y^{'} (x) + \frac{y}{x} = 2 x^{4} y^{2}

Solve Bernoulli ODE:

y = \frac{2}{x ( - x ^{4} + c _{1} )}

y = \frac{2}{x ( - x ^{4} + c _{1} )}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+y/x =2x^4y^2 ?
The solution for y^'+y/x =2x^4y^2 is y= 2/(x(-x^4+c_{1))}