What is the derivative of f(x)=x^2*e^x ?

The derivative of f(x)=x^2*e^x is 2xe^x+e^xx^2

What is the first derivative of f(x)=x^2*e^x ?

The first derivative of f(x)=x^2*e^x is 2xe^x+e^xx^2

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derivative of

f (x) = x^{2} \cdot e^{x}

2 x e^{x} + e^{x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = e^{x}

= \frac{d}{d x} (x^{2}) e^{x} + \frac{d}{d x} (e^{x}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x e^{x} + e^{x} x^{2}

\int_{1}^{4} 4 x^{2} d x

\int e^{s i n (x)} d x

5 x e^{- x} - 3 e^{x^{2}}

x \to \infty lim (1 0^{x})

(6 x)^{5 x}

What is the derivative of f(x)=x^2*e^x ?
The derivative of f(x)=x^2*e^x is 2xe^x+e^xx^2
What is the first derivative of f(x)=x^2*e^x ?
The first derivative of f(x)=x^2*e^x is 2xe^x+e^xx^2