What is the solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3} ?

The solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3} is y=-(cos(x))/(e^{x^3)}+(c_{1})/(e^{x^3)}

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(dy)/(dx)+3x^2y=sin(x)e^{-x^3}

\frac{d y}{d x} + 3 x^{2} y = sin (x) e^{- x^{3}}

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

Solution steps

\frac{d y}{d x} + 3 x^{2} y = sin (x) e^{- x^{3}}

Solve linear ODE:

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

\frac{d}{d x} (cos (sin (tan (2 π x))))

cos (x y) = 1 + sin (y)

\frac{d}{d x} (4 e^{3 x^{2}})

\frac{2 x ^{3} + 5}{4 x ^{2} + 7}

1 + x^{2}

What is the solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3} ?
The solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3} is y=-(cos(x))/(e^{x^3)}+(c_{1})/(e^{x^3)}