What is the limit as x approaches 0+of x^5ln(x) ?

The limit as x approaches 0+of x^5ln(x) is 0

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limit as x approaches 0+of x^5ln(x)

x \to 0 + lim (x^{5} ln (x))

0

Solution steps

x \to 0 + lim (x^{5} ln (x))

Rewrite for L'Hopital

= x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x ^{5}}})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{5}{x ^{6}}})

= x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{5}{x ^{6}}})

Simplify

\frac{\frac{1}{x}}{- \frac{5}{x ^{6}}} : - \frac{x ^{5}}{5}

= x \to 0 + lim (- \frac{x ^{5}}{5})

Plug in the value

x = 0

= - \frac{0 ^{5}}{5}

Simplify

- \frac{0 ^{5}}{5} : 0

= 0

x \to 1 - lim (6 x - 2)

\frac{\partial}{\partial x} (3 x^{2} y^{2} + \frac{x}{y})

y = sin (3 x + 2 y)

\int (5 - 3 x + x^{2}) d x

\frac{d}{d x} (\frac{1}{5 - x})

What is the limit as x approaches 0+of x^5ln(x) ?
The limit as x approaches 0+of x^5ln(x) is 0