What is (\partial)/(\partial x)(y*cos(x-y)) ?

The answer to (\partial)/(\partial x)(y*cos(x-y)) is -ysin(x-y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(y*cos(x-y))

\frac{\partial}{\partial x} (y \cdot cos (x - y))

- y sin (x - y)

Solution steps

\frac{\partial}{\partial x} (y cos (x - y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (cos (x - y))

Apply the chain rule:

- sin (x - y) \frac{\partial}{\partial x} (x - y)

= - sin (x - y) \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= y (- sin (x - y) \cdot 1)

Simplify

= - y sin (x - y)

7 x - 4 x^{2}

y^{^{'}} = y (4 - t y)

\frac{d}{d x} (cos^{2} (x) + sin^{2} (x))

What is (\partial)/(\partial x)(y*cos(x-y)) ?
The answer to (\partial)/(\partial x)(y*cos(x-y)) is -ysin(x-y)