What is the tangent of \sqrt[4]{x} ?

The tangent of \sqrt[4]{x} is y= 1/(4a_{0)^{3/4}}x+\sqrt[4]{a_{0}}-(a_{0}^{1/4})/4

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tangent of \sqrt[4]{x}

tangent of

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

Find the slope of

Compute the slope of

x = a_{0} : m = \frac{1}{4 a _{0}^{\frac{3}{4}}}

Find the line with slope m=

\frac{1}{4 a _{0}^{\frac{3}{4}}}

and passing through

\int \frac{e ^{x}}{e ^{4} - 1} d x

\frac{d y}{d x} = 8 y, y (0) = 6

\int \frac{x ^{2} - 29 x + 5}{( x - 4 ) ^{2} ( x ^{2} + 3 )} d x

\int_{0}^{4} 1 + 9 x d x

ln (1 - 3 y)

What is the tangent of \sqrt[4]{x} ?
The tangent of \sqrt[4]{x} is y= 1/(4a_{0)^{3/4}}x+\sqrt[4]{a_{0}}-(a_{0}^{1/4})/4