What is the tangent of f(x)= 8/x ,\at x=5 ?

The tangent of f(x)= 8/x ,\at x=5 is y=-8/25 x+16/5

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tangent of f(x)= 8/x ,\at x=5

tangent of

f (x) = \frac{8}{x}, at x = 5

y = - \frac{8}{25} x + \frac{16}{5}

Solution steps

Find the tangent point:

(5, \frac{8}{5})

Find the slope of

f (x) = \frac{8}{x} : \frac{df ( x )}{d x} = - \frac{8}{x ^{2}}

Compute the slope of

f (x) = \frac{8}{x}

x = 5 : m = - \frac{8}{25}

Find the line with slope m=

- \frac{8}{25}

and passing through

(5, \frac{8}{5}) : y = - \frac{8}{25} x + \frac{16}{5}

y = - \frac{8}{25} x + \frac{16}{5}

y^{^{''}} + y = 9 sin (x)

40 ln (3 x + 1) - \frac{x}{3}

y^{^{''}} - 7 y^{^{'}} + 7 y = 0

\int 3 x - 5 d x

\int x^{2} e^{x^{3}} d x

What is the tangent of f(x)= 8/x ,\at x=5 ?
The tangent of f(x)= 8/x ,\at x=5 is y=-8/25 x+16/5