What is the tangent of y=12sqrt(x),(9,36) ?

The tangent of y=12sqrt(x),(9,36) is y=2x+18

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tangent of y=12sqrt(x),(9,36)

tangent of

y = 12 x, (9, 36)

y = 2 x + 18

Solution steps

Find the slope of

y = 12 x : \frac{d y}{d x} = \frac{6}{x}

Compute the slope of

y = 12 x

(9, 36) : m = 2

Find the line with slope m=

2

and passing through

(9, 36) : y = 2 x + 18

y = 2 x + 18

5 y^{^{''}} + 25 y^{^{'}} + 1700 y = 10 sin (20 t)

x (3 x - 1)

2 x (x^{2} + 1)

\int 18 tan^{3} (x) d x

What is the tangent of y=12sqrt(x),(9,36) ?
The tangent of y=12sqrt(x),(9,36) is y=2x+18