What is (\partial)/(\partial x)(-7x^2+7y^2-7) ?

The answer to (\partial)/(\partial x)(-7x^2+7y^2-7) is -14x

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(\partial)/(\partial x)(-7x^2+7y^2-7)

\frac{\partial}{\partial x} (- 7 x^{2} + 7 y^{2} - 7)

- 14 x

Solution steps

\frac{\partial}{\partial x} (- 7 x^{2} + 7 y^{2} - 7)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (7 x^{2}) + \frac{\partial}{\partial x} (7 y^{2}) - \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (7 x^{2}) = 14 x

\frac{\partial}{\partial x} (7 y^{2}) = 0

\frac{\partial}{\partial x} (7) = 0

= - 14 x + 0 - 0

Simplify

= - 14 x

\frac{\partial}{\partial y} (\frac{x + y}{1 + y ^{2}})

\frac{d}{d x} (- e^{- 5 x})

(2 + x^{2}) \frac{2 - x ^{2}}{2 - x}

\int_{0}^{1} \frac{1}{2 x - 1} d x

What is (\partial)/(\partial x)(-7x^2+7y^2-7) ?
The answer to (\partial)/(\partial x)(-7x^2+7y^2-7) is -14x