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Popular >

y^'-ky=0

Solution

y^{^{'}} - k y = 0

Solution

y = e^{k t + c_{1}}

Solution steps

y^{'} (t) - k y (t) = 0

Solve separable ODE:

y = e^{k t + c_{1}}

y = e^{k t + c_{1}}

Popular Examples

tangent of y=sqrt(x)(9.3)tangent of

y = x (9.3)

integral of x^2*sin(x)

\int x^{2} \cdot sin (x) d x

y^{^{'}} - \frac{y}{x} = 2

y^{''}-7y^'+2y=te^t

y^{^{''}} - 7 y^{^{'}} + 2 y = t e^{t}

(\partial)/(\partial x)(x^2+e^{xy})

\frac{\partial}{\partial x} (x^{2} + e^{x y})

Frequently Asked Questions (FAQ)

What is the solution for y^'-ky=0 ?
The solution for y^'-ky=0 is y=e^{kt+c_{1}}