What is the tangent of f(x)=x^4,\at x=7 ?

The tangent of f(x)=x^4,\at x=7 is y=1372x-7203

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tangent of f(x)=x^4,\at x=7

tangent of

f (x) = x^{4}, at x = 7

y = 1372 x - 7203

Solution steps

Find the tangent point:

(7, 2401)

Find the slope of

f (x) = x^{4} : \frac{df ( x )}{d x} = 4 x^{3}

Compute the slope of

f (x) = x^{4}

x = 7 : m = 1372

Find the line with slope m=

1372

and passing through

(7, 2401) : y = 1372 x - 7203

y = 1372 x - 7203

\int \frac{e ^{2 x}}{1 + e ^{x}} d x

\frac{d}{d x} \frac{( x ^{2} + 32 x ^{\frac{1}{2}} )}{8}

(e^{y} + 1)^{2} e^{- y} d x + (e^{x} + 1) e^{- x} d y = 0

\frac{1}{( x - 1 ) ^{2}}

x \to 1 lim (\frac{2 - 1}{x ^{3} - 3})

What is the tangent of f(x)=x^4,\at x=7 ?
The tangent of f(x)=x^4,\at x=7 is y=1372x-7203