What is the sum from n=1 to infinity of tan(n) ?

The sum from n=1 to infinity of tan(n) is diverges

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sum from n=1 to infinity of tan(n)

n = 1 \sum \infty tan (n)

diverges

Solution steps

n = 1 \sum \infty tan (n)

Apply Series Divergence Test:

diverges

= diverges

x \to - 3 + lim (2 x^{2} + 4 x + 3)

\int \frac{x - 6}{x ^{2} - 6 x + 8} d x

\frac{d}{d x} (cos (1))

x \to 4 lim (\frac{4}{x ^{\frac{3}{2}}})

x \to - 3 lim (2 x^{2} + x^{3} + 5 x - 2)

What is the sum from n=1 to infinity of tan(n) ?
The sum from n=1 to infinity of tan(n) is diverges