What is the limit as t approaches 1 of (3t-1)(5t^2+2) ?

The limit as t approaches 1 of (3t-1)(5t^2+2) is 14

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limit as t approaches 1 of (3t-1)(5t^2+2)

t \to 1 lim ((3 t - 1) (5 t^{2} + 2))

14

Solution steps

t \to 1 lim ((3 t - 1) (5 t^{2} + 2))

Plug in the value

t = 1

= (3 \cdot 1 - 1) (5 \cdot 1^{2} + 2)

Simplify

(3 \cdot 1 - 1) (5 \cdot 1^{2} + 2) : 14

= 14

\frac{d}{d x} (sin (x) ln (9 x))

\frac{\partial}{\partial x} (e^{s i n^{2} (x)})

\int_{0}^{1} 3^{3 x} d x

\frac{1}{y ^{2}} - \frac{5}{y ^{4}} (y + 9 y^{3})

\frac{\partial}{\partial x} (sin (x y^{3}))

What is the limit as t approaches 1 of (3t-1)(5t^2+2) ?
The limit as t approaches 1 of (3t-1)(5t^2+2) is 14