What is the solution for 8(t+1)(dy)/(dt)-6y=12t ?

The solution for 8(t+1)(dy)/(dt)-6y=12t is y=2(3t+4)+c_{1}(t+1)^{3/4}

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8(t+1)(dy)/(dt)-6y=12t

8 (t + 1) \frac{d y}{d t} - 6 y = 12 t

y = 2 (3 t + 4) + c_{1} (t + 1)^{\frac{3}{4}}

Solution steps

8 (t + 1) \frac{d y}{d t} - 6 y = 12 t

Solve linear ODE:

y = 2 (3 t + 4) + c_{1} (t + 1)^{\frac{3}{4}}

y = 2 (3 t + 4) + c_{1} (t + 1)^{\frac{3}{4}}

\int_{0}^{1} (1 + 2^{x})^{2} 2^{- x} d x

\frac{\partial}{\partial x} (\cdot e)

f (x) = (x^{2} + 1) (2 - x)

x \to - 3 lim (2 x + 5)

What is the solution for 8(t+1)(dy)/(dt)-6y=12t ?
The solution for 8(t+1)(dy)/(dt)-6y=12t is y=2(3t+4)+c_{1}(t+1)^{3/4}