What is the limit as x approaches 0 of 1/(sqrt(2x)) ?

The limit as x approaches 0 of 1/(sqrt(2x)) is diverges

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limit as x approaches 0 of 1/(sqrt(2x))

x \to 0 lim (\frac{1}{2 x})

diverges

Solution steps

x \to 0 lim (\frac{1}{2 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{2 x}) = \infty

x \to 0 - lim (\frac{1}{2 x}) =

Undefined

= diverges

\frac{d}{d x} (5 x - e)

\frac{\partial}{\partial x} (\frac{6 x - 7 y}{y ^{2} + x ^{2}})

x y^{^{'}} = y + x^{2} sin (x), y (\frac{π}{6}) = 0

\frac{d}{d x} ((\frac{x ^{2} + 2}{x ^{3} - 1})^{3})

\frac{1}{s ^{3} ( s ^{2} + 1 )}

What is the limit as x approaches 0 of 1/(sqrt(2x)) ?
The limit as x approaches 0 of 1/(sqrt(2x)) is diverges