What is the solution for t^2(dy)/(dt)+y=0,y(7)=-4 ?

The solution for t^2(dy)/(dt)+y=0,y(7)=-4 is y=-4e^{(7-t)/(7t)}

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t^2(dy)/(dt)+y=0,y(7)=-4

t^{2} \frac{d y}{d t} + y = 0, y (7) = - 4

y = - 4 e^{\frac{7 - t}{7 t}}

Solution steps

t^{2} \frac{d y}{d t} + y = 0

Solve linear ODE:

y = - 4 e^{\frac{7 - t}{7 t}}

y = - 4 e^{\frac{7 - t}{7 t}}

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What is the solution for t^2(dy)/(dt)+y=0,y(7)=-4 ?
The solution for t^2(dy)/(dt)+y=0,y(7)=-4 is y=-4e^{(7-t)/(7t)}