What is laplacetransform 7+3t ?

The answer to laplacetransform 7+3t is 7/s+3/(s^2)

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laplacetransform 7+3t

laplace transform

7 + 3 t

\frac{7}{s} + \frac{3}{s ^{2}}

Solution steps

L {7 + 3 t}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {7} + 3 L {t}

L {7} : \frac{7}{s}

L {t} : \frac{1}{s ^{2}}

= \frac{7}{s} + 3 \cdot \frac{1}{s ^{2}}

Refine

\frac{7}{s} + 3 \frac{1}{s ^{2}} : \frac{7}{s} + \frac{3}{s ^{2}}

= \frac{7}{s} + \frac{3}{s ^{2}}

\int \frac{x ^{3}}{( 1 - 2 x ^{4} ) ^{5}} d x

x y^{^{''}} = y^{^{'}} + (y^{^{'}})^{3}

x \to - 3 - lim (\frac{4 x}{9 - x ^{2}})

\int \frac{1}{x ^{2} - x + 2} d x

\int \frac{1}{x ^{2} ( x ^{2} - 1 )} d x

What is laplacetransform 7+3t ?
The answer to laplacetransform 7+3t is 7/s+3/(s^2)