What is the integral of sqrt(t)-8cos(t) ?

The integral of sqrt(t)-8cos(t) is 2/3 t^{3/2}-8sin(t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sqrt(t)-8cos(t)

\int t - 8 cos (t) d t

\frac{2}{3} t^{\frac{3}{2}} - 8 sin (t) + C

Solution steps

\int t - 8 cos (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int t d t - \int 8 cos (t) d t

\int t d t = \frac{2}{3} t^{\frac{3}{2}}

\int 8 cos (t) d t = 8 sin (t)

= \frac{2}{3} t^{\frac{3}{2}} - 8 sin (t)

Add a constant to the solution

= \frac{2}{3} t^{\frac{3}{2}} - 8 sin (t) + C

\int \frac{x ^{3} - x ^{2} - 2 x}{4 x - 2} d x

x \to \infty + lim (\frac{lo g _{6} ( x )}{lo g _{8} ( x )})

\frac{d ^{5}}{d x ^{5}} (\frac{1}{x} + cos (2 x))

\frac{d}{d x} (12 x y)

f (x) = \frac{x + x}{x ^{2}}

What is the integral of sqrt(t)-8cos(t) ?
The integral of sqrt(t)-8cos(t) is 2/3 t^{3/2}-8sin(t)+C