What is the derivative of ln(x^2-1) ?

The derivative of ln(x^2-1) is (2x)/(x^2-1)

What is the first derivative of ln(x^2-1) ?

The first derivative of ln(x^2-1) is (2x)/(x^2-1)

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derivative of

ln (x^{2} - 1)

\frac{2 x}{x ^{2} - 1}

Solution steps

\frac{d}{d x} (ln (x^{2} - 1))

Apply the chain rule:

\frac{1}{x ^{2} - 1} \frac{d}{d x} (x^{2} - 1)

= \frac{1}{x ^{2} - 1} \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= \frac{1}{x ^{2} - 1} \cdot 2 x

Simplify

\frac{1}{x ^{2} - 1} \cdot 2 x : \frac{2 x}{x ^{2} - 1}

= \frac{2 x}{x ^{2} - 1}

n = 0 \sum \infty n x^{n - 1}

\frac{d}{d x} (x^{\frac{- 5}{9}})

f (x) = e^{- \frac{x ^{2}}{2}}

\int_{2}^{8} (- x + 10) d x

y d x + (1 + x) d y = 0, y (0) = 1

What is the derivative of ln(x^2-1) ?
The derivative of ln(x^2-1) is (2x)/(x^2-1)
What is the first derivative of ln(x^2-1) ?
The first derivative of ln(x^2-1) is (2x)/(x^2-1)