What is the derivative of (12-3y-2x/4) ?

The derivative of (12-3y-2x/4) is 1/4 (-3(dy)/(dx)-2)

What is the first derivative of (12-3y-2x/4) ?

The first derivative of (12-3y-2x/4) is 1/4 (-3(dy)/(dx)-2)

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\frac{d}{d x} (\frac{12 - 3 y - 2 x}{4})

\frac{1}{4} (- 3 \frac{d y}{d x} - 2)

Solution steps

\frac{d}{d x} (\frac{12 - 3 y - 2 x}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (12 - 3 y - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{d}{d x} (12) - \frac{d}{d x} (3 y) - \frac{d}{d x} (2 x))

\frac{d}{d x} (12) = 0

\frac{d}{d x} (3 y) = 3 \frac{d y}{d x}

\frac{d}{d x} (2 x) = 2

= \frac{1}{4} (0 - 3 \frac{d y}{d x} - 2)

Simplify

= \frac{1}{4} (- 3 \frac{d y}{d x} - 2)

y = x (x^{2} + 1)^{3}

\int (cos (n x)) d x

\int_{- 1}^{2} (1 - x) d x

n = 1 \sum \infty \frac{1}{3 ^{n}}

\int tan (5 θ) d θ

What is the derivative of (12-3y-2x/4) ?
The derivative of (12-3y-2x/4) is 1/4 (-3(dy)/(dx)-2)
What is the first derivative of (12-3y-2x/4) ?
The first derivative of (12-3y-2x/4) is 1/4 (-3(dy)/(dx)-2)