What is the derivative of 5/(\sqrt[5]{t)}+5t ?

The derivative of 5/(\sqrt[5]{t)}+5t is -1/(t^{6/5)}+5

What is the first derivative of 5/(\sqrt[5]{t)}+5t ?

The first derivative of 5/(\sqrt[5]{t)}+5t is -1/(t^{6/5)}+5

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derivative of

- \frac{1}{t ^{\frac{6}{5}}} + 5

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (5 t) = 5

= - \frac{1}{t ^{\frac{6}{5}}} + 5

\int 3 t^{2} sin (t^{3}) d t

\frac{d}{d x} ((x)^{3})

\int_{1}^{2} 8 r^{4} ln (r) d r

y^{^{'''}} + y^{^{''}} - 2 = 0

\int \frac{x ^{2} + 2 x + 2}{x + 1} d x

What is the derivative of 5/(\sqrt[5]{t)}+5t ?
The derivative of 5/(\sqrt[5]{t)}+5t is -1/(t^{6/5)}+5
What is the first derivative of 5/(\sqrt[5]{t)}+5t ?
The first derivative of 5/(\sqrt[5]{t)}+5t is -1/(t^{6/5)}+5