What is the tangent of f(x)=x^2-6,(2,-2) ?

The tangent of f(x)=x^2-6,(2,-2) is y=4x-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-6,(2,-2)

tangent of

f (x) = x^{2} - 6, (2, - 2)

y = 4 x - 10

Solution steps

Find the slope of

f (x) = x^{2} - 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 6

(2, - 2) : m = 4

Find the line with slope m=

4

and passing through

(2, - 2) : y = 4 x - 10

y = 4 x - 10

x \to - \infty lim (2. 3^{x})

2 y^{^{''}} + 35 y = 0

x \to 2 lim (\frac{x ^{2}}{x ^{2} + 1})

\int e^{- in x} d x

\int (sin (x) - cos (x)) d x

What is the tangent of f(x)=x^2-6,(2,-2) ?
The tangent of f(x)=x^2-6,(2,-2) is y=4x-10