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Popular >

y^'+8y=3x

Solution

y^{^{'}} + 8 y = 3 x

Solution

y = \frac{3 ( 8 x - 1 )}{64} + \frac{c _{1}}{e ^{8 x}}

Solution steps

y^{'} (x) + 8 y = 3 x

Solve linear ODE:

y = \frac{3 ( 8 x - 1 )}{64} + \frac{c _{1}}{e ^{8 x}}

y = \frac{3 ( 8 x - 1 )}{64} + \frac{c _{1}}{e ^{8 x}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+8y=3x ?
The solution for y^'+8y=3x is y=(3(8x-1))/(64)+(c_{1})/(e^{8x)}