What is the derivative of sin^2(3-x) ?

The derivative of sin^2(3-x) is -sin(6-2x)

What is the first derivative of sin^2(3-x) ?

The first derivative of sin^2(3-x) is -sin(6-2x)

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\frac{d}{d x} (sin^{2} (3 - x))

- sin (6 - 2 x)

Solution steps

\frac{d}{d x} (sin^{2} (3 - x))

Apply the chain rule:

2 sin (3 - x) \frac{d}{d x} (sin (3 - x))

= 2 sin (3 - x) \frac{d}{d x} (sin (3 - x))

\frac{d}{d x} (sin (3 - x)) = - cos (3 - x)

= 2 sin (3 - x) (- cos (3 - x))

Simplify

2 sin (3 - x) (- cos (3 - x)) : - sin (6 - 2 x)

= - sin (6 - 2 x)

\frac{d}{d x} (9 - x^{2} - y^{2})

6 u + 7 u

\frac{\partial}{\partial x} ((- (3 x + 9))^{9})

sin (arcsin (x))

3 e^{t} cos (t) - 3 e^{t} sin (t)

What is the derivative of sin^2(3-x) ?
The derivative of sin^2(3-x) is -sin(6-2x)
What is the first derivative of sin^2(3-x) ?
The first derivative of sin^2(3-x) is -sin(6-2x)