What is (\partial)/(\partial x)(cos(4xy)) ?

The answer to (\partial)/(\partial x)(cos(4xy)) is -sin(4xy)*4y

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(\partial)/(\partial x)(cos(4xy))

\frac{\partial}{\partial x} (cos (4 x y))

- sin (4 x y) \cdot 4 y

Solution steps

\frac{\partial}{\partial x} (cos (4 x y))

Treat

y

as a constant

Apply the chain rule:

- sin (4 x y) \frac{\partial}{\partial x} (4 x y)

= - sin (4 x y) \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (4 x y) = 4 y

= - sin (4 x y) \cdot 4 y

y = 6 x^{2} - 10 x - 5 x^{- 2}

\frac{\partial}{\partial x} (2 k l ln (\frac{x - n}{n - x}))

f (x) = x + 3 - 2

\int \frac{cos ( \frac{π}{x ^{10}} )}{x ^{11}} d x

\frac{d}{d x} (\frac{x + 1}{2 x - 1})

What is (\partial)/(\partial x)(cos(4xy)) ?
The answer to (\partial)/(\partial x)(cos(4xy)) is -sin(4xy)*4y