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Popular >

y^'+y=2

Solution

y^{^{'}} + y = 2

Solution

y = - e^{- t - c_{1}} + 2

Solution steps

y^{'} (t) + y = 2

Solve separable ODE:

y = - e^{- t - c_{1}} + 2

y = - e^{- t - c_{1}} + 2

Popular Examples

integral of 1/(15+4t-t^2)

\int \frac{1}{15 + 4 t - t ^{2}} d t

taylor 1/(1-x),22 taylor

\frac{1}{1 - x}, 22

inverse oflaplace s/(s^2+2)inverse laplace

\frac{s}{s ^{2} + 2}

tangent of f(x)=4x-32sqrt(x),\at x=4 tangent of

f (x) = 4 x - 32 x, at x = 4

x^2y^'+2xy-y^3=0

x^{2} y^{^{'}} + 2 x y - y^{3} = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=2 ?
The solution for y^'+y=2 is y=-e^{-t-c_{1}}+2