What is the derivative of e^{x^3+7x} ?

The derivative of e^{x^3+7x} is e^{x^3+7x}(3x^2+7)

What is the first derivative of e^{x^3+7x} ?

The first derivative of e^{x^3+7x} is e^{x^3+7x}(3x^2+7)

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\frac{d}{d x} (e^{x^{3} + 7 x})

e^{x^{3} + 7 x} (3 x^{2} + 7)

Solution steps

\frac{d}{d x} (e^{x^{3} + 7 x})

Apply the chain rule:

e^{x^{3} + 7 x} \frac{d}{d x} (x^{3} + 7 x)

= e^{x^{3} + 7 x} \frac{d}{d x} (x^{3} + 7 x)

\frac{d}{d x} (x^{3} + 7 x) = 3 x^{2} + 7

= e^{x^{3} + 7 x} (3 x^{2} + 7)

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n = 5 \sum \infty \frac{n}{( n + 1 ) !}

What is the derivative of e^{x^3+7x} ?
The derivative of e^{x^3+7x} is e^{x^3+7x}(3x^2+7)
What is the first derivative of e^{x^3+7x} ?
The first derivative of e^{x^3+7x} is e^{x^3+7x}(3x^2+7)