What is the limit as h approaches+0 of h/(sin(3h)) ?

The limit as h approaches+0 of h/(sin(3h)) is 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches+0 of h/(sin(3h))

h \to + 0 lim (\frac{h}{sin ( 3 h )})

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

h \to 0 lim (\frac{h}{sin ( 3 h )})

Apply L'Hopital's Rule

: h \to 0 lim (\frac{1}{cos ( 3 h ) \cdot 3})

= h \to 0 lim (\frac{1}{cos ( 3 h ) \cdot 3})

Plug in the value

h = 0

= \frac{1}{cos ( 3 \cdot 0 ) \cdot 3}

cos (3 \cdot 0) \cdot 3 = 3

= \frac{1}{3}

\int (0.3 y^{4} - 8 y^{- 3} + 2) d y

x \to - 1 + lim (x)

\frac{d}{d x} (\frac{( 1 + x ^{2} + x ^{4} )}{1 + x + x ^{2}})

y^{^{'}} - \frac{9}{x} y = \frac{y ^{5}}{x ^{20}}

y^{^{''}} + 16 y = sin (4 t)

What is the limit as h approaches+0 of h/(sin(3h)) ?
The limit as h approaches+0 of h/(sin(3h)) is 1/3