What is (\partial)/(\partial x)(3cos(x)-sin(x)y) ?

The answer to (\partial)/(\partial x)(3cos(x)-sin(x)y) is -3sin(x)-ycos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(3cos(x)-sin(x)y)

\frac{\partial}{\partial x} (3 cos (x) - sin (x) y)

- 3 sin (x) - y cos (x)

Solution steps

\frac{\partial}{\partial x} (3 cos (x) - sin (x) y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 cos (x)) - \frac{\partial}{\partial x} (sin (x) y)

\frac{\partial}{\partial x} (3 cos (x)) = - 3 sin (x)

\frac{\partial}{\partial x} (sin (x) y) = y cos (x)

= - 3 sin (x) - y cos (x)

\int_{1}^{3} \frac{5}{x ^{2}} d x

\frac{d}{d x} (cos (arcsin (4 x)))

\frac{d}{d x} (14 x^{6} - 5 x^{4} + 15 x^{2} - 8)

f (x) = x e^{3 x^{2}} + 1

\frac{4}{x ^{5}} - \frac{1}{x ^{2}}

What is (\partial)/(\partial x)(3cos(x)-sin(x)y) ?
The answer to (\partial)/(\partial x)(3cos(x)-sin(x)y) is -3sin(x)-ycos(x)