What is the derivative of ((mv^2))/r ?

The derivative of ((mv^2))/r is (v^2)/r

What is the first derivative of ((mv^2))/r ?

The first derivative of ((mv^2))/r is (v^2)/r

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derivative of

\frac{( m v ^{2} )}{r}

\frac{v ^{2}}{r}

Solution steps

\frac{d}{d m} (\frac{m v ^{2}}{r})

Treat

v, r

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{v ^{2}}{r} \frac{d m}{d m}

Apply the common derivative:

\frac{d m}{d m} = 1

= \frac{v ^{2}}{r} \cdot 1

Simplify

= \frac{v ^{2}}{r}

\frac{d y}{d x} = x y + 2 x

\int - \frac{20}{x ^{21}} d x

\frac{d}{d x} (e^{x} sin^{2} (x))

\int \frac{4}{175} x^{3} d x

\frac{d}{d x} (cos (tan (7 x)))

What is the derivative of ((mv^2))/r ?
The derivative of ((mv^2))/r is (v^2)/r
What is the first derivative of ((mv^2))/r ?
The first derivative of ((mv^2))/r is (v^2)/r