What is the solution for (dy)/(dt)=-6/((2000+6t)) ?

The solution for (dy)/(dt)=-6/((2000+6t)) is y=-ln(2000+6t)+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=-6/((2000+6t))

\frac{d y}{d t} = - \frac{6}{( 2000 + 6 t )}

y = - ln (2000 + 6 t) + c_{1}

Solution steps

\frac{d y}{d t} = - \frac{6}{( 2000 + 6 t )}

Substitute

\frac{d y}{d t}

with

y^{'} (t)

y^{^{'}} (t) = - \frac{6}{( 2000 + 6 t )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - \frac{6}{2000 + 6 t} d t

\int - \frac{6}{2000 + 6 t} d t = - ln (2000 + 6 t) + c_{1}

y = - ln (2000 + 6 t) + c_{1}

\int \frac{e ^{x}}{e ^{2 x} - 1} d x

(\frac{1}{2})^{x} - x

\int_{- 1}^{1} \frac{3}{4} x^{2} (1 - x^{2}) d x

\int - 5 tan^{3} (x) d x

f (3)

What is the solution for (dy)/(dt)=-6/((2000+6t)) ?
The solution for (dy)/(dt)=-6/((2000+6t)) is y=-ln(2000+6t)+c_{1}