What is the derivative of ((-sin(x)/(1-cos(x)))^2) ?

The derivative of ((-sin(x)/(1-cos(x)))^2) is (2sin(x))/((1-cos(x))(cos(x)-1))

What is the first derivative of ((-sin(x)/(1-cos(x)))^2) ?

The first derivative of ((-sin(x)/(1-cos(x)))^2) is (2sin(x))/((1-cos(x))(cos(x)-1))

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\frac{d}{d x} ((\frac{- sin ( x )}{1 - cos ( x )})^{2})

\frac{2 sin ( x )}{( 1 - cos ( x ) ) ( cos ( x ) - 1 )}

Solution steps

\frac{d}{d x} ((\frac{- sin ( x )}{1 - cos ( x )})^{2})

Apply the chain rule:

2 \cdot \frac{- sin ( x )}{1 - cos ( x )} \frac{d}{d x} (\frac{- sin ( x )}{1 - cos ( x )})

= 2 \cdot \frac{- sin ( x )}{1 - cos ( x )} \frac{d}{d x} (\frac{- sin ( x )}{1 - cos ( x )})

\frac{d}{d x} (\frac{- sin ( x )}{1 - cos ( x )}) = - \frac{1}{cos ( x ) - 1}

= 2 \cdot \frac{- sin ( x )}{1 - cos ( x )} (- \frac{1}{cos ( x ) - 1})

Simplify

2 \cdot \frac{- sin ( x )}{1 - cos ( x )} (- \frac{1}{cos ( x ) - 1}) : \frac{2 sin ( x )}{( 1 - cos ( x ) ) ( cos ( x ) - 1 )}

= \frac{2 sin ( x )}{( 1 - cos ( x ) ) ( cos ( x ) - 1 )}

\int x (x - 1) d x

\frac{d}{d x} (\frac{( 1 - x ^{2} )}{1 + x ^{2}})

\frac{\partial}{\partial x} (\frac{m \cdot x \cdot T}{A})

x \to 1 + lim (7 ∣ x + 1 ∣ - 4)

\int_{0}^{3} 9 + x^{2} d x

What is the derivative of ((-sin(x)/(1-cos(x)))^2) ?
The derivative of ((-sin(x)/(1-cos(x)))^2) is (2sin(x))/((1-cos(x))(cos(x)-1))
What is the first derivative of ((-sin(x)/(1-cos(x)))^2) ?
The first derivative of ((-sin(x)/(1-cos(x)))^2) is (2sin(x))/((1-cos(x))(cos(x)-1))