What is the derivative of y=x^2-8x+5 ?

The derivative of y=x^2-8x+5 is 2x-8

What is the first derivative of y=x^2-8x+5 ?

The first derivative of y=x^2-8x+5 is 2x-8

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derivative of

y = x^{2} - 8 x + 5

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5) = 0

= 2 x - 8 + 0

Simplify

= 2 x - 8

x \to 5 lim (1)

\frac{\partial}{\partial x} (ln (4 x + 3 y))

y^{^{'}} + 2 y = 4 cos (2 x)

\int \frac{5 x ^{4} + 8}{x ^{5} + 8 x} d x

\int cos^{3} (t) d t

What is the derivative of y=x^2-8x+5 ?
The derivative of y=x^2-8x+5 is 2x-8
What is the first derivative of y=x^2-8x+5 ?
The first derivative of y=x^2-8x+5 is 2x-8