What is the integral from 1 to 9 of 2/x ?

The integral from 1 to 9 of 2/x is 4ln(3)

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integral from 1 to 9 of 2/x

\int_{1}^{9} \frac{2}{x} d x

4 ln (3)

Decimal Notation

4.39444 \dots

Solution steps

\int_{1}^{9} \frac{2}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{9} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 2 [ln ∣ x ∣]_{1}^{9}

Compute the boundaries:

2 ln (3)

= 2 \cdot 2 ln (3)

Simplify

= 4 ln (3)

\frac{d}{d x} (- 3 csc (x^{\frac{2}{3}}))

\int x^{- 1} + sin (x) + e^{x} d x

\frac{d y}{d x} + 2 x y = 1

h \to 0 - lim (\frac{- ln ( 1 + 6 h )}{h})

2 t^{3}

What is the integral from 1 to 9 of 2/x ?
The integral from 1 to 9 of 2/x is 4ln(3)