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Popular >

y^'=-2y+5

Solution

y^{^{'}} = - 2 y + 5

Solution

y = \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

Solution steps

y^{'} (t) = - 2 y + 5

Solve separable ODE:

y = \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

y = \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

Popular Examples

derivative of (e^x/(2x+1))

\frac{d}{d x} (\frac{e ^{x}}{2 x + 1})

(\partial)/(\partial x)((-(y^2))/((x-y)^2))

\frac{\partial}{\partial x} (\frac{- ( y ^{2} )}{( x - y ) ^{2}})

t*(dy)/(dt)+y=2te^t

t \cdot \frac{d y}{d t} + y = 2 t e^{t}

integral of 1/(x^{3/5)}

\int \frac{1}{x ^{\frac{3}{5}}} d x

integral of 6cos(6x)

\int 6 cos (6 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=-2y+5 ?
The solution for y^'=-2y+5 is y=(e^{-2t-c_{1}})/2+5/2