What is the limit as x approaches 4 of x-4/(x^2-16) ?

The limit as x approaches 4 of x-4/(x^2-16) is diverges

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limit as x approaches 4 of x-4/(x^2-16)

x \to 4 lim (x - \frac{4}{x ^{2} - 16})

diverges

Solution steps

x \to 4 lim (x - \frac{4}{x ^{2} - 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (x - \frac{4}{x ^{2} - 16}) = - \infty

x \to 4 - lim (x - \frac{4}{x ^{2} - 16}) = \infty

= diverges

x^{3} - 3, [- 2, 0]

e^{3 x + 1}

\frac{d}{d x} (\frac{sin ( 5 x )}{5})

\int (2 x^{2} - 3 x + 2) d x

x \to m + lim ([x])

What is the limit as x approaches 4 of x-4/(x^2-16) ?
The limit as x approaches 4 of x-4/(x^2-16) is diverges