What is the derivative of x^2+3y^2-3 ?

The derivative of x^2+3y^2-3 is 2x+6y(dy)/(dx)

What is the first derivative of x^2+3y^2-3 ?

The first derivative of x^2+3y^2-3 is 2x+6y(dy)/(dx)

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\frac{d}{d x} (x^{2} + 3 y^{2} - 3)

2 x + 6 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} + 3 y^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 y^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 y^{2}) = 6 y \frac{d y}{d x}

\frac{d}{d x} (3) = 0

= 2 x + 6 y \frac{d y}{d x} - 0

Simplify

= 2 x + 6 y \frac{d y}{d x}

\frac{d y}{d t} + 5 y = 0

f (x) = \frac{x}{x ^{2} + 9}, at x = 4

f (x) = 2 x^{3}, (2, 16)

x \to 3 + lim (\frac{x ^{2} + 1}{x - 3})

(- 8, - 2), (1, 4)

What is the derivative of x^2+3y^2-3 ?
The derivative of x^2+3y^2-3 is 2x+6y(dy)/(dx)
What is the first derivative of x^2+3y^2-3 ?
The first derivative of x^2+3y^2-3 is 2x+6y(dy)/(dx)