What is (\partial)/(\partial x)(9ycos(xy)) ?

The answer to (\partial)/(\partial x)(9ycos(xy)) is -9y^2sin(yx)

Popular >

(\partial)/(\partial x)(9ycos(xy))

\frac{\partial}{\partial x} (9 y cos (x y))

- 9 y^{2} sin (y x)

Solution steps

\frac{\partial}{\partial x} (9 y cos (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 y \frac{\partial}{\partial x} (cos (x y))

Apply the chain rule:

- sin (x y) \frac{\partial}{\partial x} (x y)

= - sin (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 9 y (- sin (x y) y)

Simplify

9 y (- sin (x y) y) : - 9 y^{2} sin (y x)

= - 9 y^{2} sin (y x)

\frac{\partial}{\partial x} ((x^{2} + x - y)^{7})

n = 1 \sum \infty 0. 7^{n} + 0. 9^{n}

\frac{d}{d x} (6 + cos (3 x))

\int_{2}^{6} \frac{1}{2 x - 3} d x

x \to 0 + lim (\frac{3 ^{x} - 1}{x ^{2}})

What is (\partial)/(\partial x)(9ycos(xy)) ?
The answer to (\partial)/(\partial x)(9ycos(xy)) is -9y^2sin(yx)